实现二叉排序树的前中后序遍历

二叉排序树定义

二叉排序树(Binary Sort Tree),也称为二叉查找树(Binary Search Tree, BST)或有序二叉树,是一种特殊的二叉树数据结构。以下是二叉排序树的一些核心概念:

一个二叉排序树或者是一棵空树,或者是具有以下性质的二叉树:

  • 右子树上所有结点的值均大于它的根结点的值
  • 左子树上所有结点的值均小于它的根结点的值
  • 左右子树也分别为二叉排序树
  • 不存在键值相等的节点

代码实现

#include <stdio.h>
#include <stdbool.h>
#include <stdlib.h>
typedef int DataType_t; 
typedef struct BSTreeNode
{
	DataType_t 	Keyval; 
	struct BSTreeNode *lchild;
	struct BSTreeNode *rchild;
}BSTNode_t;
 BSTNode_t* BSTree_Create(DataType_t KeyVal)
{
	BSTNode_t *root = (BSTNode_t *)calloc(1,sizeof(BSTNode_t));
	if(root == NULL){
	perror("Calloc memory for the root is failed!\n");
	exit(-1);
	}
	root->lchild = NULL;
	root->rchild = NULL;
	root->Keyval = KeyVal;
	return root;
}
BSTNode_t* BSTree_NewNode(DataType_t KeyVal)
{
	BSTNode_t *New = (BSTNode_t *)calloc(1,sizeof(BSTNode_t));
	if(New == NULL){
	perror("Calloc memory for the New is failed!\n");
	return NULL;
	}
	New->lchild = NULL;
	New->rchild = NULL;
	New->Keyval = KeyVal;
	return New;
}
bool BSTree_InsertNode(BSTNode_t* root, DataType_t KeyVal)
{
 if (root == NULL) {
 printf("Error: root is NULL, cannot insert %d\n", KeyVal);
 return false;
 }
 BSTNode_t *New = BSTree_NewNode(KeyVal);
 if (New == NULL) {
 printf("Create NewNode Error\n");
 return false;
 }
 BSTNode_t *Proot = root;
 while (Proot != NULL) {
 if (KeyVal == Proot->Keyval) {
 printf("Can not Insert, duplicate value: %d\n", KeyVal);
 free(New); // 避免内存泄漏
 return false;
 }
 else if (KeyVal < Proot->Keyval) {
 if (Proot->lchild == NULL) {
 Proot->lchild = New;
 return true;
 }
 Proot = Proot->lchild;
 }
 else {
 if (Proot->rchild == NULL) {
 Proot->rchild = New;
 return true;
 }
 Proot = Proot->rchild; // 
 }
 }
 return true; //
}
//前序遍历
bool BSTree_PreOrder(BSTNode_t* root)
{
	if(root == NULL)
	{
	return false;
	}
	printf("KeyVal = %d\n",root->Keyval);
	BSTree_PreOrder(root->lchild);
	BSTree_PreOrder(root->rchild);
	return true;
}
//中序遍历
bool BSTree_InOrder(BSTNode_t* root)
{
	if(root == NULL)
	{
	return false;
	}
	BSTree_InOrder(root->lchild);
	printf("KeyVal = %d\n",root->Keyval);
	BSTree_InOrder(root->rchild);
	return true;
}
//后序遍历
bool BSTree_PostOrder(BSTNode_t* root)
{
	if(root == NULL)
	{
	return false;
	}
	BSTree_PostOrder(root->lchild);
	BSTree_PostOrder(root->rchild);
	printf("KeyVal = %d\n",root->Keyval);
	return true;
}
int main()
{
 // --- 1. 测试:创建根节点 ---
 printf("1. 创建根节点...\n");
 BSTNode_t* root = BSTree_Create(50);
 if (root) {
 printf("成功创建根节点,值为: %d\n", root->Keyval);
 }
 // --- 2. 测试:插入多个节点 ---
 printf("\n2. 插入其他节点...\n");
 int values[] = {30, 70, 20, 40, 60, 80, 35, 45};
 int n = sizeof(values) / sizeof(values[0]);
 for (int i = 0; i < n; i++) {
 if (BSTree_InsertNode(root, values[i])) {
 printf("成功插入: %d\n", values[i]);
 }
 }
 // --- 3. 测试:重复插入(应失败)---
 printf("\n3. 测试重复插入...\n");
 BSTree_InsertNode(root, 40); // 已存在
 BSTree_InsertNode(root, 50); // 根节点已存在
 // --- 4. 测试:遍历操作 ---
 printf("\n4. 遍历测试...\n");
 printf("\n=== 前序遍历 (Pre-order) ===\n");
 BSTree_PreOrder(root);
 printf("\n=== 中序遍历 (In-order) - 应升序输出 ===\n");
 BSTree_InOrder(root);
 printf("\n=== 后序遍历 (Post-order) ===\n");
 BSTree_PostOrder(root);
 	printf("\n7. 测试插入到 NULL 树(应失败)...\n");
 BSTNode_t* emptyTree = NULL;
 bool result = BSTree_InsertNode(emptyTree, 100);
 if (!result) {
 printf("正确:无法向 NULL 树插入节点。\n");
 }
 printf("\n所有测试完成\n");
 return 0;
}

根节点的值是50,主函数中依次插入节点:30, 70, 20, 40, 60, 80, 35, 45,所以这棵树的图像长这个样子

运行结果

作者:Yue+原文地址:https://www.cnblogs.com/YueZone/p/19022187

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